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(1/25)^x+4(5^x-5)=25^2x
We move all terms to the left:
(1/25)^x+4(5^x-5)-(25^2x)=0
Domain of the equation: 25)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/25)^x+4(5^x-5)-25^2x=0
We multiply parentheses
(+1/25)^x+20x-25^2x-20=0
We multiply all the terms by the denominator
(+1+20x*25)^x-25^2x*25)^x-20*25)^x=0
We add all the numbers together, and all the variables
(20x*25+1)^x-25^2x*25)^x-20*25)^x=0
Wy multiply elements
-15625x^4+(20x*25+1)^x=0
We do not support expression: x^4
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